Anton Shterenlikht wrote on 20.07.2011 17:44:
On Wed, Jul 20, 2011 at 04:55:59PM +0400, Ruslan Mahmatkhanov wrote:
As far i understand PYTHON_VERSION hold value like 'python2.7', so you
should correct this in your Makefile. Or just use USE_PYTHON = 2.6
No, PYTHON_VERSION seems to be overwritten by something else.
I removed all but the PYTHON parts from the Makefile,
and get this:
Yes, i see this in bsd.python.mk:
# Define PYTHON_VERSION to override the
# defaults that USE_PYTHON would give you.
But it seems not true. Here is my test Makefile:
mrk@smeshariki2$ cat Makefile
PORTNAME= blah
DISTVERSION= 1.0
CATEGORIES= misc
COMMENT= Some dumb port for testing
USE_PYTHON= yes
.include <bsd.port.pre.mk>
.if ${ARCH} == "i386"
PYTHON_VERSION= "python2.6"
.endif
.include <bsd.port.post.mk>
mrk@smeshariki2$ make depends
===> blah-1.0 depends on file: /usr/local/bin/python2.7 - found
===> blah-1.0 depends on file: /usr/local/bin/python2.7 - found
mrk@smeshariki2$ uname -p
i386
I added python@ to cc, since it seems like bsd.python.mk bug to me (or
documentation bug).
--
Regards,
Ruslan
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