> I must missunderstand how to use regex(3). To add a bit, running the same program on Linux gives the expected results:
regexpr=a(.)c number of substrings=1 return from regexec=0 nmatch=0 p0.so=0 p0.eo=0 p1.so=0 p1.eo=0 p2.so=0 p2.eo=0 p3.so=0 p3.eo=0 return from regexec=0 nmatch=1 p0.so=0 p0.eo=3 p1.so=0 p1.eo=0 p2.so=0 p2.eo=0 p3.so=0 p3.eo=0 return from regexec=0 nmatch=2 p0.so=0 p0.eo=3 p1.so=1 p1.eo=2 p2.so=0 p2.eo=0 p3.so=0 p3.eo=0 Olivier _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[EMAIL PROTECTED]"
