At 10:10 AM +0100 7/28/05, [EMAIL PROTECTED] wrote:
Garance wrote:
> What I do in this cases is create a script called "list_args.sh":
#!/bin/sh
printf "\nlist_args.sh at `date +%H:%M:%S` with \$# = $#\n"
# Process all parameters.
N=0
while test $# != 0 ; do
N=$(($N+1))
printf " \$$N = [%3d] '$1'\n" ${#1}
shift
done
Then in your script, replace the ldapdelete command with
list_args.sh. That way you'll see *exactly* what ldapdelete
is seeing for parameters, and that might help.
I tried that one, with an echo $* - though I assume the printf
prints it out 'more precise'?
Well, I also have versions that use an echo instead of printf.
The printf just makes it easier to have a "pretty" output.
The problem with using a plain 'echo *' is that there are
several different inputs which will produce the same output.
Compare:
echo a b
and echo "a b"
or echo "a b"
and echo "a b "
The outputs from `echo' will look the same, but the arguments to
the program are very different. That's why my script lists out
the exact arguments, with their lengths. I did that because
sometimes those details matter. I have solved problems similar
to the one which is frustrating you by using this kind of script.
--
Garance Alistair Drosehn = [EMAIL PROTECTED]
Senior Systems Programmer or [EMAIL PROTECTED]
Rensselaer Polytechnic Institute; Troy, NY; USA
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