--On October 13, 2005 4:04:45 PM -0700 Drew Tomlinson
<[EMAIL PROTECTED]> wrote:
I'm working on a script that reads a directory using 'find' and its
'-exec' primary to create a symlink to the file. So for example, I have
the following command:
find /multimedia/Pictures -iname "*.jpg" -print | cut -d'/' -f4
You'll have to play with the field value (-f) to get the right location,
but this would return only the filename.
This command returns a bunch of filenames. Here's an example of one:
/multimedia/Pictures/2005 Kimberly & Rich/IMG_1210.JPG
What I'd like to is get '-exec' to run this command:
I don't understand what you're trying to do here.
ln -s "/multimedia/Pictures/2005 Kimberly & Rich/IMG_1210.JPG" "2005
Kimberly & Rich/IMG_1210.JPG"
Are you trying to create symlinks in a different directory? If so, why not
do this?
ln -s dir1/ dir2/
Then, when you add new files to dir1/ they will automatically show up in
dir2/ because the dir is symlinked rather than the individual files.
What exactly are you trying to accomplish?
Paul Schmehl ([EMAIL PROTECTED])
Adjunct Information Security Officer
University of Texas at Dallas
AVIEN Founding Member
http://www.utdallas.edu/
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