--On Wednesday, October 08, 2008 14:16:02 -0500 Giorgos Keramidas
<[EMAIL PROTECTED]> wrote:
On Wed, 08 Oct 2008 12:11:40 +0700, Kalpin Erlangga Silaen
<[EMAIL PROTECTED]> wrote:
Dear all,
I am going to extract field username and UID from /etc/passwd and
passed into some scripts. Let say I got line
admin 100
admin2 200
admin3 300
admin4 400
and then I want to echoing into screen:
admin has uid 100
admin2 has uid 200
admin3 has uid 300
admin4 has uid 400
How do I make this with bash script?
You don't really need bash for this.
Here's a sample awk script that should work:
% cat -n /tmp/userlist.awk
1 #!/usr/bin/awk -f
2
3 {
4 print $1,"has uid",$2;
5 }
% chmod 0755 /tmp/userlist.awk
% cat /tmp/user-data
admin 100
admin2 200
admin3 300
admin4 400
% /tmp/userlist.awk < /tmp/user-data
admin has uid 100
admin2 has uid 200
admin3 has uid 300
admin4 has uid 400
%
Sure, but why use an elephant to swat a flea when
awk 'FS=":"; {print $1" has uid "$3}' /etc/passwd | sort -k 4 -n
works fine and returns the accounts in numerical order?
--
Paul Schmehl, Senior Infosec Analyst
As if it wasn't already obvious, my opinions
are my own and not those of my employer.
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