On 8/17/2010 7:47 AM, Drew Tomlinson wrote:
I have a collection of yearly top 100 Billboard mp3s in this format
(all one line - sorry if it wraps):
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028
Kenny Loggins - This Is It.mp3
I want to create symbolic links to the top 30 in 1966-1969 in another
directory for easy migration to a flash card. Thus I invoked 'find' to
get a list (again, all one line):
find -E "/archive/Multimedia/Audio/Music/Billboard Top USA Singles"
-regex '.*19[6-9][0-9]-0[0-2][0-9].*'
(OK, I know this will only return the top 29)
'find' returns the complete filename as above:
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028
Kenny Loggins - This Is It.mp3
Then I attempt to use 'basename' to extract the file name to a
variable which I can later pass to 'ln'. This seems to work:
basename "/archive/Multimedia/Audio/Music/Billboard Top USA
Singles/1980-028 Kenny Loggins - This Is It.mp3"
returns (all one line):
1980-028 Kenny Loggins - This Is It.mp3
which is what I would expect. However using it with 'find' give me
this type of unexpected result:
for i in `find -E "/archive/Multimedia/Audio/Music/Billboard Top USA
Singles" -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename "${i}";done
1980-028
Kenny
Loggins
-
This
Is
It.mp3
Why is this different? And more importantly, how can I capture the
file name to $i?
It finally occurred to me that I needed the shell to see a new line as
the delimiter and not whitespace. Then a simple search revealed my answer:
O=$IFS
IFS=$(echo -en "\n\b")
<do stuff>
IFS=$O
Sorry for the noise.
Drew
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