howdy, y'all ---
these may be stupid questions and, if so, i am prepared to slap my forehead
with the palm of my hand.
i recently acquired my first batch of intel cpus with 64_bit integer registers
[ celeron 440 ],
specifically for the 16 registers and the potential for a truly_gargantuan
datasize.
intel has called this many things, currently "intel 64 architecture".
to me, this is just a bigger, faster "386",
just like my "486" and several flavors of "pentium" [ now, all retired ].
i have never owned an amd cpu.
this may be the source of my confusion.
what prompted my recent searches was the observation, while working on my
"killer_app",
in <machine/types.h>, as i recall, that the size of an "intptr" is 32_bits.
[ i am aware of the gcc "double_integer" implementation of "64_bit"
data_integers.
that is not the issue; i want big memory.
]
i want my app to exist in two sizes, small [ 8_, 16_ and 32_bit integers and
32_bit pointers ] and
large [ 8_, 16_, 32_ and 64_bit integers and 48_bit pointers ],
the choice between the two being made by my users, according to their needs.
my objective is to produce both versions, simultaneously.
so, i have been looking at many pages, mostly at freebsd.org [ http and ftp ]
and gcc.gnu.org,
as well as some others [ release notes, in particular ].
the last question is the big one.
consider a dvd_image [ to pick an approach ] of a release to be found on
ftp.freebsd.org.
q: if the release_name includes the string "i386",
am i restricted to 8 32_bit registers and 32_bit pointers,
notwithstanding its installation on an intel_64 platform ?
next, from what i have been reading,
those releases whose names contain "amd64" not only are for amd cpus, but,
also,
are for the intel_64 variant [ no doubt, probing the cpu for its feature_set
].
q: if i install an "amd64" version on an "intel_64" platform,
am i restricted to 16 64_bit registers and 48_bit pointers or
can i compile for both cpu_models
[ perhaps, with nothing more complicated than a compiler option ] ?
please cc.
in advance, thanks big_time.
rob
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