On Thu, 02 Aug 2012 13:20:52 +0200 kaltheat wrote: > > > Hi, > > I tried to replace three letters with three letters by awk using the > sub-routine. I assumed that my regular expression does mean the > following: > > match if three letters of any letter of alphabet occurs anywhere in > input > > $ echo AbC | awk '{sub(/[[:alpha:]]{3}/,"cBa"); print;}' > AbC > > As you can see the result was unexpected. > When I try doing it for at least one letter, it works: > > $ echo AbC | awk '{sub(/[[:alpha:]]+/,"cBa"); print;}' > cBa > ... > What am I doing wrong? > Or is awk buggy?
Traditional awk implementations don't support {n}, but I think POSIX implementations should. _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"