On Thu, Jun 12, 2003 at 02:58:32PM -0400 I heard the voice of
Dave [Hawk-Systems], and lo! it spake thus:
> For example,
> <brutally pseudo script>
> for($i=30; $i>0;$1--){ # 30 days is maximum retained
> for LOG in `ls /users/*/logs/ | grep .$i'`; do
> # move any of the previous logs into the current existing
> # so that we don't add to number of logs per user
> $prevLOG = strreplace(($i-1)($i) on $LOG)
> mv $prevLOG $LOG
> done
> )
> </brutally pseudoscript>
>
> Am thinking that the shell script will need to drop to awk to perform the
> disection of the log number extensions... any thoughts on this/easier methods
> before I sit down and devote some time to it?
You want jot(1) and expr(1).
Something along the lines of:
for i in `jot 29 29 1`; do
if [ -r /some/dir/log.${i} ] ; then
mv -f /some/dir/log.${i} /some/dir/log.`expr "${i}" + 1`
fi
done
(more simplistic than yours, since it doesn't recurse across directories,
but the idea gets across)
--
Matthew Fuller (MF4839) | [EMAIL PROTECTED]
Systems/Network Administrator | http://www.over-yonder.net/~fullermd/
"The only reason I'm burning my candle at both ends, is because I
haven't figured out how to light the middle yet"
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