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Subject: segmentation fault-- is my array too long? From: "Caroline Korves" <[EMAIL PROTECTED]> Date: Thu, 06 May 2004 14:58:43 -0400 To: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Hello,
This short program below represents a problem I am having with segmentation faults in a much larger C program that has numerous arrays. Seems as though when I increase the number of elements in an array (here, for example, beyond 130,000) a seg fault occurs.
Any idea on what I should change to make the program run with large numbers of elements in my arrays?
Thanks. #include <stdlib.h> #include <stdio.h> #include <math.h>
#define td 365 /* # days in trxn season */ #define lifetab 94 /* enter 94 lines from life table, corresponds to 27-120 years */ /* # persons in run */ #define persons 150000 #define scens 4
int main() { long int j, person=0;
double ncost[persons][scens]; double nuts[persons][scens];
printf("check "); printf("\n");
for (person=0; person<persons; person++) { ncost[person][0]=0.00; ncost[person][1]=0.00; ncost[person][2]=0.00; ncost[person][3]=0.00; nuts[person][0]=0.00; nuts[person][1]=0.00; nuts[person][2]=0.00; nuts[person][3]=0.00; }
printf("persons "); printf("%d\n", persons);
return 0;
} _________________________________________________________________
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References
1. http://g.msn.com/8HMAENUS/2728??PS=47575
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Greetings, Caroline.
It could be that your array is too long. I managed to run the program (straight copy and paste), but it could be that your program isn't allocated enough memory initially to hold those two huge arrays. I might be off here, but I think a double is 8 bytes long. That means you're trying to allocate 2 * 8 * 4 * 150,000 = 9,600,000 B = 9.6 MB of memory off the heap. Seeing as how you're program is assigned a fixed amount of memory upon execution (and it seems your program isn't assigned enough), you sometimes need to allocate memory on the heap if you are to operate on arrays that big.
malloc() is your friend! :-)
--> double *ncost = malloc(sizeof (double) * persons * scens); <--
This ought to do the trick. Just remember to make sure that malloc returns a valid pointer, otherwise you'll have another seg fault.
I'm pretty sure you can adress the pointer like you do with the array there (ncost[persons][0], etc...); if not, you can always do ncost(sizeof(double) * persons + 0), etc...
/* AMENDMENT!!! */
In my haste, I totally forgot my pointer dereferencing. The correct way to reference a pointer as a two dimensional array is, of course, thus:
*(ncost + (sizeof(double) * persons) + 0)) = 0.00;
Silly me. Anyway, this should work. /* END AMMENDMENT */
Hope this helps!
-Henrik W Lund
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