Um. I feel silly asking this. But I can't work it out. I want a shell script to run as another user. I always thought this was easy to do with the setuid bit, but never tried it before. I read "man chmod" and found this:
..... 4000 (the setuid bit). Executable files with this bit set will run with effective uid set to the uid of the file owner. ..... s The set-user-ID-on-execution and set-group-ID-on-execution bits. .... And off I went. I wrote a shell script to output the current uid. I chown'ed it to another user. I "chmod +s"ed it. I ran it. It didn't work. ----- rtb27# cat test #! /bin/sh whoami rtb27# ll test -rwsr-sr-x 1 rich wheel 20 Sep 17 19:34 test rtb27# ./test root -------- Um. Help? Rich _______________________________________________ [EMAIL PROTECTED] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "[EMAIL PROTECTED]"