Hi Everyone,
I am reading an intro to shell-coding, and the following program is used as a simple example of vulnerable code:
/* vuln.c */
int
main(int argc, char **argv, char **envp)
{
char buf[256];
strcpy(buf, argv[1]);return 0; }
When I run this code like this:
18 > vuln Segmentation fault (core dumped)
it segfaults, like the tutorial says. In the tutorial this line:
19 > vuln `perl -e 'print "A"x256 . "BBBB" . "CCCC"'`
also segfaults, but not on my machine. Is this some FreeBSD security feature?
20 > uname -a FreeBSD localhost 5.3-BETA2 FreeBSD 5.3-BETA2 #0: Mon Sep 6 15:27:56 CDT 2004 [EMAIL PROTECTED]:/usr/obj/usr/src/sys/CUSTOM i386
If this doesn't cause a segfault, does it still overflow?
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