On 24 feb 2005, at 12:39, Soheil Hassas Yeganeh wrote:
You can set $[1..n] to "" and then print find ./ -name "stuff" | awk '{ $1=""; $2=""; print}
On Wed, 23 Feb 2005 22:41:32 -0500, Mark Frank <[EMAIL PROTECTED]> wrote:* On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:I'm using awk to parse a directory listing. I was hoping there is a way to tell awk to print from $2 - to the end of the columns available.
find ./ -name '*stuff' | awk '{FS="/" print $3---'}
Is this what you mean?:
find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'
thanks for the advice. No, this doesn't do what I want.
If I have a directory path /stuff/stuff/more/stuff/more/and/more that is n-levels deep, I want to be able to cut off the first two levels and print the from 2 to the Nth level.
So how about cut?
find ./ -name '*stuff'| cut -d/ -f4-
Mark
or if you insist on using awk:
find ./ -name '*stuff' | awk '{for (i=3; i<=NF; i++) printf " %s", $i; printf "\n" }'
Arno
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