Hi!
2Bart: Bart, you misinform me. Hexadecimal literals are `unsigned'
_only_ if `int' is not enough to present the value. Carefull reread of
original (in English) book of Stroustrup confirms this (in Russian edition
there is mistype). This issue is noted by Joergen Ibsen, for him this one
time generates wrong code. Example:
printf ("%s\n", (0x8000 < 0) ? "signed" : "unsigned");
printf ("%s\n", (0x4000+0x4000 < 0) ? "signed" : "unsigned");
On 32-bit platform you should add four zeros to each literal to get same
resutls, as on 16-bit platform.
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