> 1. Sum the rendered widths of the following 52 characters: > ABCDEFGHIJKLMNOPQRSTUVWXYZabcd > 2. Divide by 52 with round to nearest. The way to do it is to add > 26 and divide by 52. > 3. Multiply by 8. It's not eight spaces like some rumors say, but > eight times the average letter width.
I'm missing the context. Why are you posting this information to the
list?
Werner
