On Sat, 2008-03-01 at 10:51 +0100, Dirk Meyer wrote: > +def synchronized(lock=threading.Lock()):
With this, all functions decorated with synchronized will use the same lock. @synchronized() def foo(): ... @synchronized() def bar(): ... Ideally this code should allow foo() and bar() to execute in parallel, but it doesn't. Sure you could create a separate mutex for foo() and pass it to its synchronized() decorator, but that sucks. Also, I think threading.RLock() should be used, to allow reentrancy in the same thread. Or perhaps have a bool kwarg 'reentrant' for this. ------------------------------------------------------------------------- This SF.net email is sponsored by: Microsoft Defy all challenges. Microsoft(R) Visual Studio 2008. http://clk.atdmt.com/MRT/go/vse0120000070mrt/direct/01/ _______________________________________________ Freevo-devel mailing list Freevo-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/freevo-devel
