Number = a*10 + b
Rearranged = b*10 + a

Difference = (b - a)*10 + (a - b) = 9*(b - a)



Frank C. Wimberly
140 Calle Ojo Feliz
Santa Fe, NM 87505

wimber...@gmail.com     wimbe...@cal.berkeley.edu
Phone:  (505) 995-8715      Cell:  (505) 670-9918


-----Original Message-----
From: friam-boun...@redfish.com [mailto:friam-boun...@redfish.com] On Behalf
Of Robert J. Cordingley
Sent: Monday, October 08, 2012 10:21 AM
To: The Friday Morning Applied Complexity Coffee Group
Subject: [FRIAM] Nines: Trivia Question?

I probably should know this...

So when you rearrange the digits of a number (>9) and take the difference,
it is divisible by nine.  A result that sometimes points to accounting
errors.  If the numbers are not base 10 the result is divisible by (base-1).

What is the associated theorem for this?

Thanks
Robert



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