According to
https://github.com/fricas/fricas/blob/master/src/algebra/variable.spad#L58
the argument f is a symbol. I think that the output function is not perfect.
coerce(r : %) : OutputForm == outputMapTran(f, r)$Lisp
It leads to
%%% (409) -> function(sin(x*y), 'g, 'x, 'y)
%%% (411) -> function(sin x, 'f, 'x)
(411) f
Type: Symbol
%%% (412) -> f
(412) f x == sin(x)
Type: FunctionCalled(f)
%(409) g
Type: Symbol
%%% (410) -> g
(410) g (x, y) == sin(x y)
Type: FunctionCalled(g)
What is OK for one argument (without parentheses), is not OK for two
arguments. There is a space between g and the open (. Of course, since
the OutputForm is wrong neither i-output.boo not the TeXFormat get it
right. TeX output looks like
g \ {\left( x, \: y \right)}\ == \ {\cos \left({{y+x}} \right)}
But there are also cases like this:
%%% (468) -> )clear prop g
%%% (468) -> g(n|n>1 and odd? n, t | t > 9) == tanh n + t
%%% (469) -> g
(469) g ((n, t) | n > 1 and odd?(n) and t > 9) == tanh(n) + t
Type: FunctionCalled(g)
whose corresponding OutputForm is this:
(CONCATB g
(PAREN (| (PAREN (AGGLST n t)) (and (and (> n 1) (odd? n)) (> t 9))))
== (+ (tanh n) t))
I guess, the definition of outputMapTran would have to be changed to
really produce just (f x) or (g x y) for the function application side
(left-hand side) in case that there is no conditional part.
I leave that to someone else.
Ralf
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