> ps: can anyone explain how (well, why!) the -p11..& tail works? :)
Despite of my poor golf-score (107), I understood this one...
perl -pe'11..&' is the same as:
while(<>){
11..&;
} continue {
print;
}
The .. must be understood as the flip-flop operator: eval first part until it
gets true, then eval second part until it gets true.
When evaluating a test that is a single number, perl compares with line
number (ie, $.).
So the script tests if $. is equal at 11, when this becomes true (it has
already printed the 10 first lines), perl tries to evaluate the second part.
But second part is a call to the 'Main::' subroutine, which does not exist:
perl crashes.
There is however a problem with this script: it _does_ output something on
STDERR. What about that, Santa?
Jerome
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