En r�ponse � Piers Cawley <[EMAIL PROTECTED]>: > Ian Phillipps <[EMAIL PROTECTED]> writes: > >> --- Tim Ayers ------------------------ 21 > >> #!/usr/bin/perl > >> printf"%010d\n",$.,<> > > > > Harumph. I remember something like this approach flitting through my > > mind, but, I thought, the $. would be evaluated before the <>, so it > > would be zero. > > > > Moral: try it! > > > > Hmm... why isn't it zero? > > Because perl passes arguments by reference. So $. gets shoved on the > stack (as $.) and <> gets evaluated in an array context so that the > results can be shoved on the stack. So, when printf comes to read the > value of $. '<>' has already been evaluated.
So I guess #!/usr/bin/perl printf"%010d\n","$.",<> would print 0000000000 whatever the file. Doing what Ian thought it would do. -- Philippe BRUHAT - BooK When you run from your problem, you make it that much harder for good fortune to catch you, as well. (Moral from Groo The Wanderer #14 (Epic))
