On Mon, Jan 21, 2002 at 10:50:06AM -0500, Bernie Cosell wrote:
> On 21 Jan 2002, at 15:12, Simon Cozens wrote:
> > On Mon, Jan 21, 2002 at 03:00:57PM +0000, Robin Houston wrote:
> > > In an ideal world it would behave the same as
> > > %a = (%b, %c);
> > > for my $k (keys %a) {
> > > $a{$k} += $b{$k} if exists($b{$k}) && exists($c{$k});
> > > }
> >
> > It's not impossible that it would end up doing just that.
>
> [...]
>
> [this being a sort of inner-join, and if you like you could have
> something like an outer-join, where the non-exists element of the other
> hash would be treated as a '0'.]
My code snippet was supposed to implement the "outer join" idea.
Are you saying that it doesn't?
.robin.
