On Thu, 31 Jan 2002, Pradeep Sethi wrote:
> Thanks but I am looking of any regexp substitution.
>
> sorry for typo : I need to change 9/9/1973 to 09/09/1973
>
>
---
$date="9/09/1973";
$date=~s{(\d+/)} {$1<10?"0$1":$1}ge;
print $date,$/;
---
Can't comment on effiency ??? also will do stange things to the year it it is
incorrect:
try $date="1/1/1"; :)
Yours Tony.
/*
* "The significant problems we face cannot be solved at the
* same level of thinking we were at when we created them."
* --Albert Einstein
*/
