I am confused, I thought if in first case we declar var as hash, then we do
my %var;
and then later :
/(.*?)\s*=\s*(.*)/ and $$var{$1} = $2 while <FILE>;
-Pradeep
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 05, 2002 2:47 PM
To: Pradeep Sethi
Subject: Re: Study group for motivated people wanting to learn Perl.
The following message is a courtesy copy of an article
that has been posted to perl.beginners as well.
>>>>> "Pradeep" == Pradeep Sethi <[EMAIL PROTECTED]> writes:
Pradeep> /(.*?)\s*=\s*(.*)/ and $var{$1} = $2 while <FILE>;
Pradeep> did u mean ?
Pradeep> /(.*?)\s*=\s*(.*)/ and $var->{$1} = $2 while <FILE>;
Not necessarily. The first uses %var, the second uses $var containing
a hashref. Both are completely valid.
--
Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095
<[EMAIL PROTECTED]> <URL:http://www.stonehenge.com/merlyn/>
Perl/Unix/security consulting, Technical writing, Comedy, etc. etc.
See PerlTraining.Stonehenge.com for onsite and open-enrollment Perl
training!
