On Wed, 13 Feb 2002, Bill -OSX- Jones wrote:
> Given:
>
> #!perl
> while(<DATA>){
>
> for $x(split//){
>
> print "X:$x S:$#_ \n";
> }}
> __END__
> 1963
>
>
> Why is $#_ a -1 ???
Because $#_ is the value of the last index of @_, which does not appear to
be defined anywhere.
I think you just want $_ here?
-- Brett
http://www.chapelperilous.net/
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The health of a democratic society may be measured by the quality
of functions performed by private citizens.
-- Alexis de Tocqueville
