On Apr 11, Jeff 'japhy' Pinyan said: >On Apr 11, Paul Makepeace said: > >>The task is to find the first differing character given two strings. > >You can get a little niftier if you're using Perl 5.6: > > ($a^$b)=~/^\0*/&&$+[0]
Duh. Remove the ^ and change the && to * and you save two chars: ($a^$b)=~/\0*/*$+[0] The regex always succeeds -- thus, always returns 1. -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ ** Look for "Regular Expressions in Perl" published by Manning, in 2002 ** <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course. [ I'm looking for programming work. If you like my work, let me know. ]
