Dan Brian <[EMAIL PROTECTED]> wrote: > > Given a list of numbers, say, 1..12 for the months, and knowing the > month (i.e. 6), assign a list that is ((6..12),(1..5)). > > Assuming July, I have: > > $m = 6; > @ordered = ((1..12)[$m..11],(1..$m)); > > What if the original list was 0..11?
Use wrap-around indexing (eg, july: [-6..5]): $ perl -lwe' > @mon = qw(jan feb mar apr may jun jul aug sep oct nov dec); > $m = pop; > print "@mon[$m - 12 .. $m - 1]"' 6 jul aug sep oct nov dec jan feb mar apr may jun $ p
