I just changed it and ran into an error, so I modified the line and it
now works fine:
$__app__.security.encode_id( '%s' % $input1.id )
What was the 'file.' originally for?
Le 24/08/2011 15:00, Louise-Amélie Schmitt a écrit :
Thanks a lot!
I found another way to do it but it is awfully more complicated so
I'll change as soon as I have some time.
Best,
L-A
Le 23/08/2011 19:49, Nate Coraor a écrit :
Louise-Amélie Schmitt wrote:
Hi,
I would need to make a tool that can get the API dataset id out of
the input dataset of the tool, how can I do that?
Hi L-A,
Pass in as an argument:
$__app__.security.encode_id( 'file.%s' % $input1.id )
Where 'input1' is the param name of your input.
--nate
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