Bruce schrieb: > On Thursday 05 March 2009 01:34:29 Rolf-Werner Eilert wrote: >> newString = Conv(st, "UTF-8", "ASCII") >> >> Replace(st, "½", ".5") > > Thanks RW, > > That got me started at least. > > So far: > TRY wx = Conv(lp1[5], "UTF-8", "ASCII") > TRY wx = Replace(wx, "½", ".5") > TRY wx = Replace(wx, "¼", ".25") > TRY wx = Replace(wx, "¾", ".75") > seems to work. > > I had to put the TRY's in because 3/4 doesn't seem to handle properly > otherwise. >
Sorry, I forgot this: you must replace 3/4 to something else before you can Conv to ASCII. Arrrgh - this will not run. Next idea: Look into the string and find out what Conv makes out of "3/4" in ASCII - maybe it just makes "3/4" out of it? This is what you will have to look for. Your thing would then read as follows: > TRY wx = Conv(lp1[5], "UTF-8", "ASCII") > TRY wx = Replace(wx, "½", ".5") > TRY wx = Replace(wx, "¼", ".25") > TRY wx = Replace(wx, "3/4", ".75") We would need a String.Replace() function here... Rolf ------------------------------------------------------------------------------ Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H _______________________________________________ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
