jbskaggs a écrit :
>
> I came up with a way to random sort listview. (Iuse this for random
> shuffling card slots on games) But it isnt efficient some pointers if you
> dont mind?
>
> I use two listviews one to sort from and one to sort to:
>
> I first copy all the listitems from list 1 to list 2 EXCEPT the key for
> listview2 items = the integer from my for next loop
>
> eg
> for i = 0 to listview1.count -1 step 1
> listview2.add(i, listview1.item.text)
> next
>
> then with a for next loop based on the length of list1 I copy the
> listview.item key to a string A and listview.item.text to second string B
>
> Then I calculate a random number the count of listview2 and add that to a
> integer C
> thenadd it to listview2
> listview2.add("n"&A, B,,C) "n"&A creates a key of n1, n2, etc ...
>
>
> AFter the loop ends
>
> I run a second loop
>
> and run
> for i = 0 to listview1.count -1 step 1
> listview.moveto(i)
> listview2.item.delete
> next
>
> This gives me a random sorted list in viewlist2 of viewlist1 with no
> duplicates etc-
>
> But is there a more efficient way of doing this?
>
> here is total code:
>
> PUBLIC SUB button3_click()
> DIM a AS String
> DIM d AS Integer
> DIM e AS Integer
> DIM i AS Integer
> DIM c AS Integer
> listview1.Clear 'clears the list
> FOR i = 0 TO 199 STEP 1 'number of items to add
> listview2.Add(i, "Slot" & i) 'adds items to sort to list
> NEXT 'next item
> i = 0
>
> FOR i = 0 TO 199 STEP 1 'number of items
> e = 0
> listview1.MoveTo(i) 'goto item
> a = listview1.Item.Text 'get text
> PRINT a
> d = listview1.Key 'get key
> PRINT "old key", d
> listview1.Item.Delete 'delete item (the cut part of cut and paste)
> e = Round(Rnd(200)) ' make sure old key doesNOT equal NEW Key
> PRINT e, "<<<< the randomimzed number"
>
> IF e >= 200 THEN e = 199
> listview2.Add("n" & d, "n" & a,, e) 'adds cut items after randomly
> chosen item
> listview3.Add("n" & d, "n" & a)
> PRINT "new key", e
> NEXT 'next item down
>
> FOR i = 0 TO 199 STEP 1 'number of items
> listview2.MoveTo(i)
> listview2.Item.Delete
> NEXT
>
> ValueBox1.value = listview1.Count
> END
>
> JB SKaggs
Hi,
Let say you want to populate an array with 0-199 randomly
(please note that I write this directly, so check carefully
the syntax)
dim myArray as integer[200]
dim A as integer
dim i as integer
FOR i=0 to 199
A=int(Rnd(200-i))
' I think we could use a Swap instruction
' instead of the 2 instructions below
myArray[i]=A
myArray[A]=i
NEXT
That's all
If these numbers was the keys of the initial Listview you
just have to populate the second Listview in the new order
Hope this help
Dominique Simonart
------------------------------------------------------------------------------
This SF.net email is sponsored by:
High Quality Requirements in a Collaborative Environment.
Download a free trial of Rational Requirements Composer Now!
http://p.sf.net/sfu/www-ibm-com
_______________________________________________
Gambas-user mailing list
Gambas-user@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/gambas-user
