2011/11/13 nando <nand...@nothingsimple.com>:
> If i'm not mistaken, the +1 at the end chould not be there.
true
>
> for i =1 to len (sValue)+1
>
>
>
>
> ---------- Original Message -----------
> From: Fabien Bodard <gambas...@gmail.com>
> To: i...@eilert-sprachen.de, mailing list for gambas users
> <gambas-user@lists.sourceforge.net>
> Sent: Fri, 11 Nov 2011 15:58:17 +0100
> Subject: Re: [Gambas-user] Counting characters
>
>> maybe with gb.pcre : regexp
>>
>> or
>> Public Function CountChar(sValue as string, sChar as string) as integer
>> dim i, iRet as integer
>>
>> for i =1 to len (sValue)+1
>> if mid(sValue,i,1)=sChar then inc iRet
>> next
>>
>> return iRet
>> end
>>
>> print CountChar("coucou ça va ?", "a")
>>
>> $ 2
>>
>> Or a super version thet remember a position:
>>
>> Public Function GetCharPos(sValue as string, sChar as string) as integer[]
>> dim i as integer
>> dim aRet as new integer[]
>>
>> for i =1 to len (sValue)+1
>> if mid(sValue,i,1)=sChar then aRet.add(i)
>> next
>>
>> return aRet
>> end
>>
>> print GetCharPos("Hello how are you", "e").Count
>>
>> 2011/11/11 Rolf-Werner Eilert <eilert-sprac...@t-online.de>:
>> > Hi all,
>> >
>> > just a short question: Is there a function which simply counts how many
>> > times a character appears within a string? I vaguely remember a long
>> > time ago I used such a thing, but it may as well have been in another
>> > context.
>> >
>> > The only way I have found yet was using Split() and then count the
>> > number of resulting parts -1 IF it is more than 0.
>> >
>> > Any better way?
>> >
>> > Rolf
>> >
>> > ------------------------------------------------------------------------------
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>> >
>>
>> --
>> Fabien Bodard
>>
>> ------------------------------------------------------------------------------
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>> https://lists.sourceforge.net/lists/listinfo/gambas-user
> ------- End of Original Message -------
>
>
> ------------------------------------------------------------------------------
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--
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