Le 24/12/2016 à 09:44, Fabien Bodard a écrit : > Public Sub Main() > > Dim s As String > Dim i As String > Dim a As New Integer[] > ''1) with no knowledge of the number of values > 'init the string > s = "[12,32,3]" > > 'remove unused spaces and braquets > For Each i In Split(Left(Right(Trim(s), -1), -1)) > > a.Add(i) > > Next > > > > 'display the array content > For Each i In a > Print i > Next > > 2016-12-24 7:29 GMT+01:00 adamn...@gmail.com <adamn...@gmail.com>: >> Baffled! >> >> I have a string, like "[1,3]", that I want to populate an integer array from. >> >> How to? >> >> tia >> >> -- >> B Bruen <adamn...@gnail.com (sort of)> >>
Other solution : MyIntegerArray = JSON.Decode(MyString) :-) -- Benoît Minisini ------------------------------------------------------------------------------ Developer Access Program for Intel Xeon Phi Processors Access to Intel Xeon Phi processor-based developer platforms. With one year of Intel Parallel Studio XE. Training and support from Colfax. Order your platform today.http://sdm.link/intel _______________________________________________ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
