File.Load is working fine. It is just loading a file that has a
trailing "\n". Split then adds an empty string as the last entry in the
array. This is Split's documented behaviour. Adding the True option
suppresses empty entries. Note that Split will also add an empty entry
for any blank lines ie "\n\n". The True option will also suppress those
empty entries.
A word of caution: the True option will not suppress lines that are
comprised entirely of spaces. I'd test to see if those kind of lines
also cause problems.
On 2017-07-04 10:28 PM, Fernando Cabral wrote:
I have found and worked around the problem. When you do the following:
*Dim Expressions as string[] =
Split(File.Load("/home/fernando/.config/libreoffice/4/user/basic/indesejaveis.txt"),
"\n") *
The last item pushed into *Expressions* is an empty string ("") even though
it DOES NOT exist
in the file. So, the expressions are compiled one after the other til the
last one, that is empty. Then the program crashes.
So it seems there is a bug in the *load.file()*. Bug that I was able to
compensate for by adding the option *True* in the call to the functions
*split()*.
2017-07-04 22:29 GMT-03:00 Fernando Cabral <fernandojosecab...@gmail.com>:
Concerning RegExp I have another mysterious thing to understand
If I do something like:
*Searchfor.Push("Word")Searchfor.Push("Power")Searchfor.Push("The
same")For Each searchedfor In searchfor re.Compile(searchedfor,
re.utf8)Next*
The expression gest compiled. No error.
Neverthelesse, if I the same words from a file, using this expression:
*Dim Searchfor As New String[] = Split(File.Load("Strings"), "\n")*
re.Compile will not work. It will display an error message saying there is
nothing to compile. Now, if I do:
*print "@" & Searchfor[n] &"@\n"*
in both cases I will see precisely the same output. I can't distinguish
one from the other. So, why it compiles in the first case, but does not in
the second?
This is the mystery I must solve with a little help from a good soul out
there.
- fernando
--
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