------- Additional Comments From schlie at comcast dot net  2005-02-02 17:54 
-------
Because the "big number" exceeds the representable precision of a double,
thereby 1 is less significant than the least significant representable magnitude
of the stored value, thereby can't effect it if summed.




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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=19765

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