------- Comment #1 from igodard at pacbell dot net 2005-10-31 10:32 ------- Sorry, screwed up the explanation. Should be:
The access to "inc" is "s->inc()". "s" is a "F<T>*", which after parameter substitution is a "G<int>*". "b1<T>" is a public base of G<T>, which after substitution means that "b1<int>" is a public base of "G<int>" and so is also a public base of "s". Hence the protected member "b1<int>::inc" should be visible via "s", but is not. -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=24592
