The code:
class foo {
public:
template<typename T>
foo(int i) : j(i) {}
template<typename T>
void bar(int i) { j = i; }
template<typename T>
static
void baz(int i) {}
int j;
};
int main() {
foo::baz<bool>(3);
foo* p; p->bar<bool>(3);
new foo<bool>(3);
return 0;
}
gets you:
~/ootbc/chips$ g++ foo.cc
foo.cc: In function âint main()â:
foo.cc:8: error: âfooâ is not a template
foo.cc:8: error: no matching function for call to âfoo::foo(int)â
foo.cc:1: note: candidates are: foo::foo(const foo&)
The constructor was declared as a template, and declaring other functions works
OK.
I can believe that parsing a templated constructor for a templated class is
tough and so declaring templated constructors may be illegal. But if it is
illegal to have templated constructors then the error should be flagged at the
attempted declaration of one, rather than this peculiar message at the
invocation site. But it looks to me like the parser hit the "<" in "foo<", saw
that foo was not a template, and gave up before looking to see that the foo
constructor *was* a template.
--
Summary: Fails to accept templated constructor
Product: gcc
Version: 4.1.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: igodard at pacbell dot net
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=29008
