------- Comment #3 from photon at seznam dot cz 2007-09-18 15:12 ------- (In reply to comment #1) > No, "B" is correct. > > > A &Aref = Binst; > Aref = Cinst; > > is the same as: > Binst = (A)Cinst; >
The compiler treats this case as Ainst = (A) Cinst. -- photon at seznam dot cz changed: What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution| |INVALID http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33470