------- Comment #7 from dominiq at lps dot ens dot fr 2009-06-01 12:25 ------- > Then this is the gist of the matter - my FA textbook does not require the > argument to converge, but just the modulus, so our understandings of infinity > differ.
Think of something like \rho\exp(i\rho\sin(\pi\rho)): it is going to infinity when \rho goes to +infinity, but you cannot define a directed infinity since the argument keeps oscillating when \rho increases. -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=40318
