http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52973
Bug #: 52973
Summary: visibility attribute for class is not passed to its
members
Classification: Unclassified
Product: gcc
Version: 4.7.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: regression
AssignedTo: unassig...@gcc.gnu.org
ReportedBy: holger.h...@sap.com
In following code, gcc-4.7 does not accept the visibility attribute
defined in the class declaration:
template <class T> class __attribute__((visibility("default"))) a
{
public:
/* A */ static int c;
};
class __attribute__((visibility("default"))) b : a <b> {};
template<> /* B */ int a<b>::c = 0;
With g++-4.7, a<b>::c is hidden, with g++-4.6 (and before) it is not.
$ g++-4.7 -fvisibility=hidden -c def.cpp && objdump -Ct def.o | grep "a<b>"
0000000000000000 g O .bss 0000000000000004 .hidden a<b>::c
$ g++-4.6 -fvisibility=hidden -c def.cpp && objdump -Ct def.o | grep "a<b>"
0000000000000000 g O .bss 0000000000000004 a<b>::c
Setting the default visibility at /* A */ or /* B */ works with
g++-4.7, but I think that it still should work also with the code above.
