http://gcc.gnu.org/bugzilla/show_bug.cgi?id=53609
Jonathan Wakely <redi at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Keywords| |rejects-valid
Status|UNCONFIRMED |NEW
Last reconfirmed| |2012-06-08
CC| |dodji at gcc dot gnu.org
Summary|Wrong variadic template |Wrong variadic template
|pack expansion |pack expansion in alias
| |template
Ever Confirmed|0 |1
Known to fail| |4.7.0, 4.8.0
--- Comment #1 from Jonathan Wakely <redi at gcc dot gnu.org> 2012-06-08
09:49:33 UTC ---
Confirmed.
It works fine if you rewrite it without alias templates:
template<int...I> struct NumList { typedef List< Z<I...> > type; };
then use NumList::type instead of NumList, so the problem is with the alias
template substitution.
G++ seems to be treating Z<I>... as Z<I...> in the type-id of the
alias-declaration.
