http://gcc.gnu.org/bugzilla/show_bug.cgi?id=57133
--- Comment #3 from grpintar at gmail dot com 2013-05-01 12:43:28 UTC ---
(In reply to comment #1)
> (In reply to comment #0)
> > typedef char *type;
> >
> > void f(const type t)
> > {
>
> This doesn't do what you think it does. t is now a const variable of type
> char*, not a variable of type const char*. Observe:
>
> > cat pr57133.c
> typedef char *type;
> void f(const type t) { t = 0; }
> void g(const type t) { *t = 0; }
> > gcc -Wall -S pr57133.c
> pr57133.c: In function 'f':
> pr57133.c:2:1: error: assignment of read-only parameter 't'
>
> The warning in your main() is correct.
I see. Sorry.
