https://gcc.gnu.org/bugzilla/show_bug.cgi?id=62274

            Bug ID: 62274
           Summary: [C++11] Variadic templates expansion into non-variadic
                    class template
           Product: gcc
           Version: 4.9.0
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
          Assignee: unassigned at gcc dot gnu.org
          Reporter: juchem at gmail dot com

The code below won't compile for gcc 4.9.0, 4.8.1 and 4.7.3. Tested in Debian
sid (aug/2014), http://gcc.godbolt.org/ and http://ideone.com.

#include <type_traits>
using namespace std;

struct bar { typedef double foo; };

template <typename T>
using get_foo = typename T::foo;

template <template <typename...> class T>
struct baz {
  template <typename... UArgs>
  using type = T<UArgs...>;
};

int main() {
  return !std::is_same<double, baz<get_foo>::type<bar>>::value;
}

error output:
prog.cpp: In substitution of ‘template<class T> using get_foo = typename T::foo
[with T = UArgs ...]’:
prog.cpp:13:26:   required from ‘struct baz<get_foo>’
prog.cpp:17:49:   required from here
prog.cpp:8:32: error: ‘UArgs ...’ is not a class, struct, or union type
 using get_foo = typename T::foo;
                                ^
prog.cpp: In function ‘int main()’:
prog.cpp:17:59: error: template argument 2 is invalid
  static_assert(std::is_same<double, baz<get_foo>::type<bar>>::value,
"mismatch");

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