https://gcc.gnu.org/bugzilla/show_bug.cgi?id=80009

--- Comment #7 from Walt Brainerd <walt.brainerd at gmail dot com> ---
I took "not processed by" to mean that there is no DT edit descriptor
corresponding to it.

But I see how this might be interpreted otherwise.

Intel agrees with me FWIW.

Maybe this is a question for J3 (or perhaps first, c.l.f?).

Thanks for thinking about this.


On Sun, Mar 12, 2017 at 2:28 PM, jvdelisle at gcc dot gnu.org <
gcc-bugzi...@gcc.gnu.org> wrote:

> https://gcc.gnu.org/bugzilla/show_bug.cgi?id=80009
>
> --- Comment #6 from Jerry DeLisle <jvdelisle at gcc dot gnu.org> ---
> (In reply to Walt Brainerd from comment #1)
> > Forgot to add:
> >
> > Pls see F08 std 9.6.3(7) 2nd bullet
>
> I see:
>
> BULLET: If a list item of derived type in a formatted input/output
> statement is
> not processed by a defined input/output procedure, that list item is
> treated as
> if all of the components of the list item were specified in the list in
> component order; those components shall be accessible in the scoping unit
> containing the
> input/output statement and shall not be pointers or allocatable.
>
> In your case you have provided a defined output procedure. So this is what
> it
> is trying to do. see 'if' ... 'not processed by' above.
>
> Do I have the right place in the standard you were looking at? Maybe we
> are not
> interpreting that correctly?
>
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