https://gcc.gnu.org/bugzilla/show_bug.cgi?id=70893
Jonathan Wakely <redi at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution|--- |INVALID
--- Comment #8 from Jonathan Wakely <redi at gcc dot gnu.org> ---
The little_endian flag only affects the "external representation" not the
in-memory representation. Because the external representation for
codecvt_utf8_utf16 is UTF-8 it ignores the little_endian flag.
If you want to convert UTF-16BE to UTF-8 I think you need to treat UTF-16BE as
the external representation, so you need to use std::codecvt_utf16 to convert
it to some internal representation, and then convert that to UTF-8. So the
right way to write that function would be:
template<bool big_e> inline std::string std_utf16_to_utf8(const char *s, size_t
sz)
{
using namespace std; sz &= ~1;
// Convert UTF-16BE to UCS4 (with native endianness):
wstring_convert<codecvt_utf16<char32_t>, char32_t> conv1("");
std::u32string u32str = conv1.from_bytes(s, s+sz);
// Convert UCS4 (with native endianness) to UTF-8:
wstring_convert<codecvt_utf8<char32_t>, char32_t> conv2("");
return conv2.to_bytes(u32str);
}
