https://gcc.gnu.org/bugzilla/show_bug.cgi?id=98130

Jakub Jelinek <jakub at gcc dot gnu.org> changed:

           What    |Removed                     |Added
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                 CC|                            |jakub at gcc dot gnu.org

--- Comment #3 from Jakub Jelinek <jakub at gcc dot gnu.org> ---
So, shouldn't the code match what the comment says?
  /* If the call is to a replaceable operator delete and results
     from a delete expression as opposed to a direct call to
     such operator, then we can treat it as free.  */
There is no check that it is a replaceable operator, that would mean
testing also
  && DECL_IS_REPLACEABLE_OPERATOR (fndecl)

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