https://gcc.gnu.org/bugzilla/show_bug.cgi?id=98709

--- Comment #1 from Marc Glisse <glisse at gcc dot gnu.org> ---
At the end of gimple, we have
  _6 = a_3(D) ^ b_4(D);
  _1 = ~_6;
  _2 = a_3(D) == b_4(D);
  _7 = _1 & _2;
I guess we are missing a simplification of ~(a^b) to a==b for bool (similar to
~(a!=b) be we canonicalize != to ^).

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