https://gcc.gnu.org/bugzilla/show_bug.cgi?id=99797
Bug ID: 99797 Summary: accessing uninitialized automatic variables Product: gcc Version: 11.0 Status: UNCONFIRMED Severity: normal Priority: P3 Component: c Assignee: unassigned at gcc dot gnu.org Reporter: muecker at gwdg dot de Target Milestone: --- Consider the following example which accesses an uninitialized variable: static volatile int d = 0; void bar(int c); void foo(void) { char c; //&c; //char *p = &c; if (!c) bar(0); if (d) c = 1; if (c) bar(1); } GCC produces code where 'bar' is called twice. According to the C standard, the code is UB so this is technically OK. Still I think it is dangerous and I would prefer a more consistent behavior. When taking the address and assigning it to 'p' GCC produces code which actually checks the variable 'd'. I am not sure why this happens (it is unnecessary). Still when taking the address of 'c' the code is not UB and the generated code is OK. Finally, when taking the address and not assigning it, the code is the same as for the first case where 'bar' is called twice. This seems incorrect as the code is not UB (according to my reading of the C standard). Ideally, I think GCC should reject code when it is clearly UB (address not taken). If it does not reject the code, I think it should assume an unspecified yet consistent value is read. Producing code that assumes c == 0 and c != 0 at different points in time (without intervening write) is really dangerous and should be avoided.