https://gcc.gnu.org/bugzilla/show_bug.cgi?id=104358
Bug ID: 104358 Summary: Assignable template lambda as function parameter is incorrectly reduced to type of "int" Product: gcc Version: 12.0 Status: UNCONFIRMED Severity: normal Priority: P3 Component: c++ Assignee: unassigned at gcc dot gnu.org Reporter: nickhuang99 at hotmail dot com Target Milestone: --- Please see code at https://www.godbolt.org/z/o3bxxsYPK All other compilers parses this correctly. #include <functional> #include <type_traits> using namespace std; //1. I have a callback which happens to be an assignable lambda template<typename T> using Lambda=decltype(+[](T){}); // which is esstially a function pointer static_assert(is_same_v<Lambda<int>, void(*)(int)>); //2. Here is my data handle function which takes a data and the callback template<typename T> auto foo(T&&, Lambda<T>)->T; //3. However, parser consider the callback as type of "int" static_assert( ! is_same_v<decltype(&foo<int>), int(*)(int&&, void(*)(int))>); // lambda type is always considered as "int" static_assert(is_same_v<decltype(&foo<int>), int(*)(int&&, int)>); static_assert(is_same_v<decltype(&foo<bool>), bool(*)(bool&&, int)>); // this is impossible as callback CANNOT be "int" static_assert( ! is_same_v<Lambda<int>, int>); //////////////////////////////////////////// //4. This won't happen for a traditional function pointer template<typename T> using FunPtr=void(*)(T); static_assert(is_same_v<FunPtr<int>, void(*)(int)>); //5. let's define a similar function with callback template<typename T> auto bar(T&&, FunPtr<T>)->T; // there is no way for parser to consider callback as type of "int" static_assert(is_same_v<decltype(&bar<int>), int(*)(int&&, void(*)(int))>);