https://gcc.gnu.org/bugzilla/show_bug.cgi?id=111747
--- Comment #2 from oplata.kes1 at mail dot ru --- (In reply to Andrew Pinski from comment #1) > > 32bit floating point has the following characteristics: > Sign bit: 1 bit > Exponent width: 8 bits > Significand precision: 24 bits (23 explicitly stored) > > > 50000000 is 0x2faf080 which is more than 24bits in precision which means it > cannot be represented exactly and when you start to add 1 to something which > is greater than 0xfffff0 (which is what 1.67772e+07 is), the value stays the > same and you start to lose precision. Thank you very much!