https://gcc.gnu.org/bugzilla/show_bug.cgi?id=114240
--- Comment #7 from GCC Commits <cvs-commit at gcc dot gnu.org> --- The master branch has been updated by Jonathan Wakely <r...@gcc.gnu.org>: https://gcc.gnu.org/g:3e8ee03edd018eed43444755f601cdb9d5931654 commit r14-9406-g3e8ee03edd018eed43444755f601cdb9d5931654 Author: Jonathan Wakely <jwak...@redhat.com> Date: Fri Mar 8 16:15:57 2024 +0000 libstdc++: Do not require a time-of-day when parsing sys_days [PR114240] When parsing a std::chrono::sys_days (or a sys_time with an even longer period) we should not require a time-of-day to be present in the input, because we can't represent that in the result type anyway. Rather than trying to decide which specializations should require a time-of-date and which should not, follow the direction of Howard Hinnant's date library, which allows extracting a sys_time of any period from input that only contains a date, defaulting the time-of-day part to 00:00:00. This seems consistent with the intent of the standard, which says it's an error "If the parse fails to decode a valid date" (i.e., it doesn't care about decoding a valid time, only a date). libstdc++-v3/ChangeLog: PR libstdc++/114240 * include/bits/chrono_io.h (_Parser::operator()): Assume hours(0) for a time_point, so that a time is not required to be present. * testsuite/std/time/parse/114240.cc: New test.
