https://gcc.gnu.org/bugzilla/show_bug.cgi?id=117610
--- Comment #3 from Alejandro Colomar <alx at kernel dot org> ---
(In reply to Xi Ruoyao from comment #2)
> No, it *is* initializing a pointer. You cannot initialize a struct with 0.
> Instead the initializer is considered "flattened" in C.
>
> For example:
>
> struct s2 {
> int *x;
> int y;
> };
>
> int t;
>
> int
> main(void)
> {
> struct s2 a2[] = {0, 1, &t, 2};
> _Static_assert(sizeof(a2) == sizeof(struct s2) * 2);
> }
Ahhh, you're right. That's shown in EXAMPLE 5 (p29) in
<https://www.open-std.org/jtc1/sc22/wg14/www/docs/n3220.pdf#subsection.6.7.11>.
(I'm not sure which of the weird paragraphs specify this exactly.)
How about adding a diagnostic for flat initializers? :-)
